In the above chemical reaction sequence,"A" a | vedclass

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(A) $1$. The first step involves the oxidative cleavage of $1$-methylcyclohexene using ozone $(O_3)$ followed by reductive workup with $Zn / H_2O$. Th

Vedclass · Accepted Answer

$O_3, Zn / H_2O$ and $NaOH_{(aq)} / I_2$

Vedclass · Answer

(A) $1$. The first step involves the oxidative cleavage of $1$-methylcyclohexene using ozone $(O_3)$ followed by reductive workup with $Zn / H_2O$. This reaction is known as ozonolysis,which breaks the double bond to form a dicarbonyl compound ($6$-oxoheptanal). Thus,"$A$" is $O_3, Zn / H_2O$.$2$. The second step involves the reaction of the resulting ketone group with $NaOH$ and $I_2$. This is the iodoform test,which specifically reacts with methyl ketones to produce a carboxylate salt and iodoform $(CHI_3)$. Therefore,"$B$" represents the reagents for the iodoform test,which are $NaOH_{(aq)} / I_2$ (often written as $NaOH / I_2$).$3$. Comparing these with the given options,option $A$ is the correct choice.

In the above chemical reaction sequence,"$A$" and "$B$" respectively are:

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The above conversion can be achieved by:

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